graph/dijkstra.hpp

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Last update: 2025-05-09 08:40:27+00:00
Include: #include "graph/dijkstra.hpp"

Depends on

graph/graphtemplate.hpp

Verified with

Code

#pragma once
#include "graphtemplate"
#include <bits/stdc++.h>
using namespace std;
// ダイクストラ法を用いて単一始点最短経路を求める ただし、負辺が存在しないこと O(m log n)
template<class T = int, bool directed = false, bool weighted = true>
vector<T> dijkstra(graph<T, directed, weighted>& g, int from = 0) {
    vector<T> dist(g.size(), numeric_limits<T>::max()); dist[from] = T{};
    vector<bool> visited(g.size());
    priority_queue<pair<T, int>, vector<pair<T, int>>, greater<pair<T, int>>> q;
    q.push({T{}, from});
    while (!q.empty()) {
        auto [t, x] = q.top(); q.pop();
        if (visited[x]) continue;
        visited[x] = true;
        for (auto& _e : g[x]) {
            int y = _e.to;
            if (dist[x] + _e.cost < dist[y]) {
                dist[y] = dist[x] + _e.cost;
                q.push({dist[y], y});
            }
        }
    }
    return dist;
}
// ダイクストラ法を用いて二点間最短経路を求める ただし、負閉路が存在しないこと O(m log n)
template<class T = int, bool directed = false, bool weighted = true>
T dijkstra(graph<T, directed, weighted>& g, int from, int to) {
    return dijkstra(g, from)[to];
}

#line 2 "graph/graphtemplate.hpp"
#include<bits/stdc++.h>
using namespace std;
// 辺の構造体 edge(from, to, cost, id)
template<class T = int>
struct edge {
    int from, to;
    T cost;
    int id;
};
// 頂点の構造体 vector<edge<T>>
template<class T = int>
using edges = vector<edge<T>>;
// グラフの構造体 graph<T, directed, weighted> 
template <class T = int, bool directed = false, bool weighted = false>
struct graph {
    bool isdirected, isweighted;
    edges<T> _edges;
    vector<edges<T>> data;
    T sumcost;
    graph() = default;
    // 頂点数 n のグラフを作成する
    graph(int n) : isdirected(directed), isweighted(weighted), data(n), sumcost(T{}) {}
    // from から to へ辺を追加する
    void add_edge(int from, int to, T cost = 1, int id = -1) {
        if (id == -1) id = _edges.size();
        data[from].push_back(edge<T>(from, to, cost, id));
        _edges.push_back(edge<T>(from, to, cost, id));
        if (!isdirected) {
            data[to].push_back(edge<T>(to, from, cost, id));
        }
        sumcost += cost;
    }
    // 辺を追加する
    void add_edge(edge<T> _e) {
        add_edge(_e.from, _e.to, _e.cost, _e.id);
    }
    // 標準入力から辺を読み込む
    void read(int m, int indexed = 1) {
        for (int i=0; i<m; i++) {
            int from, to;
            T cost = 1;
            cin >> from >> to;
            if (isweighted) cin >> cost;
            add_edge(from - indexed, to - indexed, cost);
        }
    }
    // 頂点数を返す
    int size() {
        return data.size();
    }
    // 頂点を返す
    edges<T> operator[](int k) {
        return data[k];
    }
    vector<int> path_to_vertex(edges<T>& _e) {
        vector<int> re;
        if (_e.size() == 0) {
            return re;
        }
        if (_e.size() == 1) {
            re.push_back(_e[0].from);
            re.push_back(_e[0].to);
            return re;
        }
        int x=_e[0].from,y=_e[0].to;
        if (x==_e[1].to || x == _e[1].from) swap(x, y);
        re.push_back(x);
        for (int i=1; i<_e.size(); i++) {
            re.push_back(y);
            x = _e[i].to;
            if (x == y) x = _e[i].from;
            swap(x, y);
        }
        return re;
    }
    edges<T> vetex_to_path (vector<int>& v){
        edges<T> re;
        for (int i=0; i+1<v.size(); i++) {
            for (auto& _e : this[v[i]]) {
                if (_e.to == v[i+1]) {
                    re.push_back(_e);
                    break;
                }
            }
        }
        return re;
    }
};
#line 4 "graph/dijkstra.hpp"
using namespace std;
// ダイクストラ法を用いて単一始点最短経路を求める ただし、負辺が存在しないこと O(m log n)
template<class T = int, bool directed = false, bool weighted = true>
vector<T> dijkstra(graph<T, directed, weighted>& g, int from = 0) {
    vector<T> dist(g.size(), numeric_limits<T>::max()); dist[from] = T{};
    vector<bool> visited(g.size());
    priority_queue<pair<T, int>, vector<pair<T, int>>, greater<pair<T, int>>> q;
    q.push({T{}, from});
    while (!q.empty()) {
        auto [t, x] = q.top(); q.pop();
        if (visited[x]) continue;
        visited[x] = true;
        for (auto& _e : g[x]) {
            int y = _e.to;
            if (dist[x] + _e.cost < dist[y]) {
                dist[y] = dist[x] + _e.cost;
                q.push({dist[y], y});
            }
        }
    }
    return dist;
}
// ダイクストラ法を用いて二点間最短経路を求める ただし、負閉路が存在しないこと O(m log n)
template<class T = int, bool directed = false, bool weighted = true>
T dijkstra(graph<T, directed, weighted>& g, int from, int to) {
    return dijkstra(g, from)[to];
}